How do you multiply #(- 7x ^ { 2} p ^ { 4} ) ( 6y ^ { 6} x ^ { 4} )#?

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Answer 1 · 2017-07-14T13:50:55

See a solution process below:

First, we can rewrite this expression as:

#(-7 * 6)p^4(x^2 * x^4)y^6 =>#

#-42p^4(x^2 * x^4)y^6#

Now, we can use this rule of exponents to multiply the #x# terms:

#x^color(red)(a) xx x^color(blue)(b) = x^(color(red)(a) + color(blue)(b))#

#-42p^4(x^color(red)(2) * x^color(blue)(4))y^6 =>#

#-42p^4x^(color(red)(2)+color(blue)(4))y^6 =>#

#-42p^4x^6y^6#