How do you solve #-4( 2+ 5a ) = 32#?

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Answer 1 · 2017-07-14T22:44:16

Multiply the #-4# through the parentheses:

#-8-20a=32#

Collect like terms:

#-20a=40#

Divide both sides by #-20#:

#a=40/-20=-2#

Answer 2 · 2017-07-14T22:48:14

#a=-2#

#-4(2+5a)=32#

#2+5a=-8# #-># divide both sides by #-4#

#5a=-10# #-># subtract #2# from both sides

#a=-2# #-># divide both sides by #5#