Question #c1acc

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Answer 1 · 2017-07-14T22:56:35

Domain: #[1, oo]#
Range: #[0, oo]#

#f(x)=sqrt(x+2-3)#

#f(x)=sqrt(x-1)#

The number under the radical cannot be negative; it must be greater than or equal to #0#.

#x-1 >= 0#
#x>=1#

Using the same logic, f(x) cannot be negative--only positive.

In interval notation, we can write it as follows:

Domain: #[1, oo]#
Range: #[0, oo]#

graph{sqrt(x-1) [-10, 10, -5, 5]}
We can check our answer by graphing the function.