Question

How do you add `\frac { - 7} { 2d } + \frac { 3} { 8d }`?

Answer 1

See a solution process below:

Explanation:

First, we need to put the fractions over a common denominator (in this case `8d`) by multiplying the fraction on the left by the appropriate form of `1`:

`(4/4 xx (-7)/(2d)) + 3/(8d) => (-28)/(8d) + 3/(8d)`

We can now add the numerators over the common denominator:

`(-28)/(8d) + 3/(8d) => (-28 + 3)/(8d) => -25/(8d)`