How do you solve #4w + 3w - 2= 19#?

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Answer 1 · 2017-07-15T18:02:42

See a solution process below:

First, combine like terms on the left side of the equation:

#(4 + 3)w - 2 = 19#

#7w - 2 = 19#

Next, add #color(red)(2)# to each side of the equation to isolate the #w# term while keeping the equation balanced:

#7w - 2 + color(red)(2) = 19 + color(red)(2)#

#7w - 0 = 21#

#7w = 21#

Now, divide each side of the equation by #color(red)(7)# to solve for #w# while keeping the equation balanced:

#(7w)/color(red)(7) = 21/color(red)(7)#

#(color(red)(cancel(color(black)(7)))w)/cancel(color(red)(7)) = 3#

#w = 3#