How do you solve #\frac { j - 18} { 2} = 1#?

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Answer 1 · 2017-07-15T22:29:16

See a solution process below:

First, multiply each side of the equation by #color(red)(2)# to eliminate the fraction while keeping the equation balanced:

#color(red)(2) xx (j - 18)/2 = color(red)(2) xx 1#

#cancel(color(red)(2)) xx (j - 18)/color(red)(cancel(color(black)(2))) = 2#

#j - 18 = 2#

Now, add #color(red)(18)# to each side of the equation to solve for #j# while keeping the equation balanced:

#j - 18 + color(red)(18) = 2 + color(red)(18)#

#j - 0 = 20#

#j = 20#