How do you factor #-36h ^ { 2} - 48h k - 15k ^ { 2}#?

1 Answer
Jul 16, 2017

See a solution process below:

Explanation:

Because there is an #h^2# and #k^# on each end of the expression and an #hk# term in the middle we know the factor must have the form:

#(ah + bk)(ch + dk)#

To find #a#, #b#, #c# and #d# we need to play with factors of #-36# and #-15#. This gives:

#(-6h - 3k)(6h + 5k)#