Step 1) Multiply each side of the equation by #color(red)(40)color(blue)(x)# to eliminate the fractions while keeping the equation balanced:
#color(red)(40)color(blue)(x) xx 3/40 = color(red)(40)color(blue)(x) xx 5/x#
#cancel(color(red)(40))color(blue)(x) xx 3/color(red)(cancel(color(black)(40))) = color(red)(40)cancel(color(blue)(x)) xx 5/color(blue)(cancel(color(black)(x)))#
#3x = 200#
Step 2) Divide each side of the equation by #color(red)(3)# to solve for #x# while keeping the equation balanced:
#(3x)/color(red)(3) = 200/color(red)(3)#
#(color(red)(cancel(color(black)(3)))x)/cancel(color(red)(3)) = 200/3#
#x = 200/3#