Question

How do you simplify `\frac { c ^ { 2} d } { c ^ { 3} d ^ { - 2} }`?

Answer 1

`d^3/c`

Explanation:

separating by variables:
`c^2/c^3=c^(2-3)=c^-1 or 1/c`
`d/d^-2=d^(1-(-2))=d^3`

therefore... `(c^2d)/(c^3d^-2)=1/cxxd^3=d^3/c`