How do you solve #0.2= ( 0.15) ^ { 3x }#?

1 Answer
Jim G.
Jul 16, 2017

#~~0.2828" to 4 dec. places"#

Explanation:

#"using the "color(blue)"law of logarithms"#

#•color(white)(x)logx^nhArrnlogx#

#color(blue)"take the ln (natural log. ) of both sides"#

#rArrln(0.2)=ln(0.15)^(3x)#

#rArr3xln(0.15)=ln(0.2)#

#rArrx=ln(0.2)/(3ln(0.15))~~0.2828#

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