How do you solve #-x ^ { 3} - 152= 64#?

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Answer 1 · 2017-07-16T14:30:13

See a solution process below:

First, add #color(red)(152)# to each side of the equation to isolate the #x# term while keeping the equation balanced:

#-x^3 - 152 + color(red)(152) = 64 + color(red)(152)#

#-x^3 - 0 = 216#

Next, multiply each side of the equation by #color(red)(-1)# to convert the #x# term to a positive while keeping the equation balanced:

#color(red)(-1) xx -x^3 - 0 = color(red)(-1) xx 216#

#x^3 - 0 = -216#

#x^3 = -216#

Now, take the cube root of each side of the equation to solve for #x# while keeping the equation balanced:

#root(3)(x^3) = root(3)(-216)#

#x = -6#