How do you solve #\frac { 3} { 4} ( x + 8) > \frac { 1} { 2} ( 2x + 10)#?

1 Answer
Jul 16, 2017

#x < 4#

Explanation:

Since one denominator is 4 and the other is 2, multiply both sides by #4# to get rid of both denominators:

#3/4(x+8) > 1/2(2x+10)#

#4*3/4(x+8) > 4*1/2(2x+10)#

#color(white)"-" 3(x+8) > 2(2x+10)#

Now, distribute the #3# and #2#, respectively.

#color(white)"-" 3*x + 3*8 > 2*2x + 2*10#

#color(white)"-." 3x + 24 > 4x + 20#

Subtract #3x# from both sides.

#color(white)"-.."3x+24 - 3x > 4x + 20 - 3x#

#24 > x + 20#

Finally, subtract #20# from both sides.

#color(white)"-" 24 - 20 > x + 20 - 20#

#color(white)"-" 4 > x#

Flip the inequality so #x# is on the left (this is optional but recommended). Remember to flip the sign as well!

#color(white)"-" x < 4#

Final Answer