Question #1a790

1 Answer
Jul 16, 2017

#x=pin#

Explanation:

#sin^2x=2sinx#
#sin^2x-2sinx=0#
#sinx(sin x - 2)=0#

#sinx = 0 #
#x=0, pi # on unit circle #-> x= pin#

#sin x - 2=0#
#sin x =2#
#x =sin^-1(2)#
This is undefined.

So, #x=pin#, where #n# is any integer.