Question

How many Oxygen atoms in 1.44 x 10^5 kg of Nitrogen Oxide?

Answer 1

Well, I will do it for `NO_2(g)`........and get over six million moles......

Explanation:

But of course there is `NO` and `N_2O`.........

For `NO_2`, we have a molecular mass of `46.01*g*mol^-1`.

And thus `"Moles of"` `NO_2` `=` `(1.44xx10^8*g)/(46.01*g*mol^-1)`

`-=3.13xx10^6*mol`....and thus `6.26xx10^6*mol` `"oxygen atoms."`

Then, you continue to solve for the number of oxygen atoms.

`6.26xx10^6*molxx6.022 * 10^23*mol^-1~= 4.0xx10^30` `"oxygen atoms"` which is nearer to the given answer.