Question

An object with a mass of `12 kg`, temperature of `210 ^oC`, and a specific heat of `7 J/(kg*K)` is dropped into a container with `32 L` of water at `0^oC`. Does the water evaporate? If not, by how much does the water's temperature change?

Answer 1

`DeltaT=208.8^circC` The water will evaporate.

Explanation:

`210^circC~~483K`
`0^circC~~273K`
`32L=0.032m^3~=0.032kg`

`m_oC_oDeltaT_o=m_wC_wDeltaT_w`

`12*7*(483-T)=0.032*4.18*(273+T)`

#40572-84T=36.51648+0.13376T

`84.13376T=40535.4835`

`T=40535.4835/84.13376=481.798074K=208.798074^circC~~208.8^circC`

`0+208.8=208.8^circC`

As `208.8gt100` the water will evaporate.