Question

Question #7dd0d

Answer 1

`s=600.25`

Explanation:

To get `sqrt(s)` on its own, we multiply both sides by `sqrt(s)/0.336`.

`0.336*color(red)(sqrt(s)/0.336)=(1.96*4.2)/sqrt(s)*color(red)(sqrt(s)/0.336)`

`(cancel(0.336)color(red)(sqrt(s)))/cancel(0.336)=(1.96*4.2*cancel(color(red)(sqrt(s))))/(color(red)(0.336)cancel(sqrt(s)`

`(sqrt(s))^2=s=((1.96*4.2)/0.336)^2=600.25`

Answer 2

See a solution process below:

Explanation:

First, evaluate the numerator of the fraction on the right side of the equation:

`0.336 = (1.96 * 4.2)/sqrt(s)`

`0.336 = 8.232/sqrt(s)`

Next, multiply each side of the equation by `color(red)(sqrt(s))` to eliminate the fraction and keeping the equation balanced:

`0.336 xx color(red)(sqrt(s)) = 8.232/sqrt(s) xx color(red)(sqrt(s))`

`0.336sqrt(s) = 8.232/color(red)(cancel(color(black)(sqrt(s)))) xx cancel(color(red)(sqrt(s)))`

`0.336sqrt(s) = 8.232`

Then, divide each side of the equation by `color(red)(0.336)` to isolate the radical while keeping the equation balanced:

`(0.336sqrt(s))/color(red)(0.336) = 8.232/color(red)(0.336)`

`(color(red)(cancel(color(black)(0.336)))sqrt(s))/cancel(color(red)(0.336)) = 24.5`

`sqrt(s) = 24.5`

Now, square both sides of the equation to solve for `s` while keeping the equation balanced:

`(sqrt(s))^2 = 24.5^2`

`s = 600.25`