A 1.85 mole sample of the ionic compound Al2(SO4)3 contains how many moles of the following? A) Al atoms B) S atoms C) Al3^+
1 Answer
(a)
(b)
(c)
Explanation:
We're asked to find the number of moles of some species in
(a)
The moles of
#"Al"# atoms:There are
#2# atoms of#"Al"# per unit of#"Al"_2"(SO"_4")"_3# , so there are two moles of#"Al"# per mole of#"Al"_2"(SO"_4")"_3# :
#1.85cancel("mol Al"_2"(SO"_4")"_3)((2color(white)(l)"mol Al")/(1cancel("mol Al"_2"(SO"_4")"_3))) = 3.70# #"mol Al"#
(b)
The moles of
#"S"# atoms:There are
#3# atoms of#"S"# per units of#"Al"_2"(SO"_4")"_3# , so there are#3# moles of#"S"# per mole** of#"Al"_2"(SO"_4")"_3# :
#1.85cancel("mol Al"_2"(SO"_4")"_3)((3color(white)(l)"mol S")/(1cancel("mol Al"_2"(SO"_4")"_3))) = 5.55# #"mol S"#
(c)
The moles of
#"Al"^(3+)# ions:The number of ions of
#"Al"^(3+)# will be the same as the number of atoms of#"Al"# , so the answer will be the same as that for (a) (assuming I understand the question correctly).