The Grand Canyon is 1800 meters deep at its deepest point. A rock is dropped from the rim above this point. What is the height of the rock as a function of time, t in seconds? How long will it take the rock to hit the canyon floor?
2 Answers
Explanation:
In different treatments, I've seen
The rock hits the canyon floor when
Acceleration due to gravity is
Velocity at time
So
Position (height) is the antiderivative of velocity.
Thus
(We disregard the negative solution because our story involves only times after
function of height of stone in respect to the starting point:
It takes approximately 19.1663s for the stone to hit the ground.
Explanation:
Solving using Physics
Function of displacement in term of time
Use the kinetic equation:
Time taken for stone to hit the ground (travels 1800m down)