Question

How do you condense `log 2 ln 8 +5 ln z`?

Answer 1

`ln(root(ln10)(8^ln2)*z^5)`

Explanation:

We know that `logx=lnx/ln10` so let's use this.

`log2ln8+5lnz=ln2/ln10*ln8+lnz^5=`

`ln8^(ln2/ln10)+lnz^5=ln(root(ln10)(8^ln2)*z^5)`