How do you solve #\frac { 1} { 5} x ^ { 2} - \frac { 29} { 25} x - \frac { 6} { 25} = 0#?

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Answer 1 · 2017-07-20T07:04:07

#x=6# or #x=-1/5#

Step 1) First, let's make all the fractions have the same denominators:

#1/5x^2-29/25x-6/25=0#

Becomes,

#5/25x^2-29/25x-6/25=0#

Step 2) Then, make them as one fraction

#(5x^2-29x-6)/25=0#

Step 3) Multiply both sides of the equation by #25#

#5x^2-29x-6=0#

Step 4) Factor

#5x^2-29x-6=0#

Becomes,

#(x-6)(5x+1)=0#

Step 5) Solve for x
#x=6# or #x=-1/5#