Question

A rectangular pool has an area of `750` `ft^2`. The length is 16 feet longer than the width. How do you find the dimensions of the pool?

Answer 1

`x=\sqrt{814}-8,\:x=-8-\sqrt{814}`

Explanation:

The pool has an area of 750 square feet. Area formula is `A=lxxw`

Since the length is 16 feet longer than the width, let's make the width `x` and the length `x+16`.
So `w=x` and `l=x+16`.

`\therefore750=x(x+16)`

`750=x^2+16x` distributive property
`0=x^2+16x-750` take all values to one side
quadratic formula here

answer: `x=\sqrt{814}-8,\:x=-8-\sqrt{814}`