How do you solve #3( 2x + 2) = 26#?

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Answer 1 · 2017-07-21T00:15:04

#x=10/3#

Begin by distributing the #3# to #2x# and #2#:

#color(red)3*2x+color(red)3*2=26#

#6x+6=26#

Subtract #6# from both sides:

#6x+cancel(6-6)=26-6#

#6x=20#

Divide #6# to both sides:

#cancel6/cancel6x=20/6#

Simplify if desired:

#x=(20divide2)/(6divide2)=10/3#