How do you solve #-2x + 10= - 20#?

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Answer 1 · 2017-07-21T02:34:38

See a solution process below:

Step 1) Subtract #color(red)(10)# from each side of the equation to isolate the #x# term while keeping the equation balanced:

#-2x + 10 - color(red)(10) = -20 - color(red)(10)#

#-2x + 0 = -30#

#-2x = -30#

Step 2) Divide each side of the equation by #color(red)(-2)# to solve for #x# while keeping the equation balanced:

#(-2x)/color(red)(-2) = (-30)/color(red)(-2)#

#(color(red)(cancel(color(black)(-2)))x)/cancel(color(red)(-2)) = 15#

#x = 15#