Question

Question #dab99

Answer 1

`(3x^3+9x^2+6x+18)/(2x^6+20x^4+42x^3)`

Explanation:

I'm not sure, but I think that this is what you're asking

`(3x+9)/(4x^4) xx (2x^3 +4x)/(x^3+10x+21)`

Lucky for us, multiplying fractions is pretty straightforward. We multiply straight across; the numerators together and the denominators together

`(3x+9)/(4x^4) xx (2x^3 +4x)/(x^3+10x+21)`

`((3x+9)(2x^3+4x))/((4x^4)(x^3+10x+21))`

let's factor and simplify the easy stuff

`((3(x+3))(cancel(2)cancel(x)(x^2+2)))/((cancel(2)cancel(x)(2x^3))(x^3+10x+21))`

`(3(x+3)(x^2+2))/((2x^3)(x^3+10x+21))`

distributive property

`(3x^3+9x^2+6x+18)/(2x^6+20x^4+42x^3)`