How do you divide #\frac { 8y ^ { 2} - 6y - 3} { 2y - 1}#?

2 Answers
Robert W.
Jul 22, 2017

#4y-1 -4/(2y-1)#

Explanation:

I had to use algebraic division for this one:enter image source here

Jim G.
Jul 22, 2017

#4y-1-4/(2y-1)#

Explanation:

#"one way is to use the divisor as a factor in the numerator"#

#"consider the numerator"#

#color(red)(4y)(2y-1)color(magenta)(+4y)-6y-3#

#=color(red)(4y)(2y-1)color(red)(-1)(2y-1)color(magenta)(-1)-3#

#=color(red)(4y)(2y-1)color(red)(-1)(2y-1)-4#

#"quotient "=color(red)(4y-1)," remainder "=-4#

#rArr(8y^2-6y-3)/(2y-1)=4y-1-4/(2y-1)#

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