Question

Peter has twice as much as Meg. Meg has $4 more than Stevie. Together they have a total of $48. How much does Meg have?

Answer 1

Meg has 13$

Explanation:

Let the money with Stevie be x

Money with Meg= x+4
Money with Peter=2(x+4)

Together they have 48$
Therefore,
`x+(x+4)+2(x+4)=48`
`x+x+4+2x+8=48`
`4x+12=48`
`4x=36`
`x=9`
Therefore,Stevie has 9$
So, Meg has 13$

Answer 2

Meg has `$13`

Explanation:

Let P denotes Peter, M denotes Meg , S denotes stevie.

Condition given ,

`P=2M ; M = S +4 :. S= M-4; P+M+S= 48` or

`P+M+S= 48 or 2M + M + M-4 =48` or

`4M-4 =48 or 4M=52 or M=13`

Meg has `$13` [Ans]

Answer 3

Peter has `$26`

Meg has `$13`

Stevie has `$9`

Explanation:

Let's say Peter's money is equal to `x` ,

Meg's `y` and Stevie's `z` :

So it is true that :

`x=2y`
`y=4+z`
`x+y+z=48`

We mus solve this system, so let's substitude the first and second equations to the last one :

`2y+4+z+z=48 iff 8+2z+4+2z=48 iff 4z=36iff`

`z=36/4=9`

`y=4+z=4+9=13`

`x=2y=2*13=26`

So Peter has `$26`

Meg `$13`

Stevie `$9`