How do you find two consecutive integers whose sum is 211?
1 Answer
Jul 22, 2017
Explanation:
"integers are 1 unit apart"
"let n be an integer then a consecutive integer is n + 1"
rArrn+(n+1)=211larr" solve for n"
rArr2n+1=211
"subtract 1 from both sides"
2ncancel(+1)cancel(-1)=211-1
rArr2n=210
"divide both sides by 2"
(cancel(2) n)/cancel(2)=210/2
rArrn=105" and " n+1=105+1=106
"thus the 2 consecutive integers are " 105" and "106
