Question

How many molecules, and how many ATOMS, are present in a `1*g` mass of nitrogen gas?

Answer 1

Of dinitrogen, there are `1/28xxN_A` molecules..., where `N_A="Avogadro's Number"`, i.e. `N_A=6.022xx10^23*mol^-1`

Explanation:

And the number of nitrogen atoms is `1/14*N_A`.

`N_A="Avogadro's number"`, `=6.022xx10^23*mol^-1`.

Why use such an absurdly large number? Well, if we got `N_A` `"hydrogen atoms"` we have a mass of `1*g` of hydrogen precisely. We got `1*g` of dinitrogen.......

And thus we got..........

`(1*g)/(28.0*g*mol^-1)xxN_A=??"nitrogen molecules"`.....

`(1*g)/(14.0*g*mol^-1)xxN_A=??"nitrogen atoms"`