How do you solve #-9+ \frac { x } { - 2} \leq - 7#?

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Answer 1 · 2017-07-24T04:17:19

#x <= -4#

We need to isolate #x#

#-9 + x/(-2) <= -7#

add #9# to both sides

#x/(-2) <= 2#

multiply #-2# on both sides

#cancel(-2) xx x/(cancel(-2)) <= -2 xx 2#

#x <= -4#