Question

How do you find the product of `(3x^3)/(8x)*16/x`?

Answer 1

You will need to multiply the numbers top X top, and bottom X bottom and add the exponents in the same way. After that you will need to simplify by dividing and exponent subtraction if necessary.

Explanation:

We have: `(3x^3)/(8x)*16/x`

`(3x^3)/(8x)*16/x = (48x^3)/(8x^2)to` by multiplying `3x^3*16=48x^3` and adding exponents to get the denominator: `8x*x=8x^2`

`(48x^3)/(8x^2)=(cancel(48x^3)6x)/cancel(8x^2)=6xto` by dividing `48/8` and subtracting exponents to reduce the fraction: `x^3/x^2 = x`

Then: `(3x^3)/(8x)*16/x=6x`

Answer 2

`6x`

Explanation:

`(3x^3)/(8x) xx16/x`

If you cancel factors in the numerator and denominator first, it makes the numbers smaller.

Cancel the numbers and simplify the variables in the denominators by adding the indices:

`(3x^3)/(cancel8x) xxcancel16^2/x = (6x^3)/(x^2)`

To divide with indices, subtract them:

`(6x^3)/(x^2) = 6x`