Question

Question #2f05d

Answer 1

The balanced equation of the reaction.

`CaCO_3(s)+2HCl->CO_2+CaCl_2+H_2O`

`" "1mol" "" "2mol" "" "1"mol" equiv22.4L" at STP"`

100 mL `1M" "HCl` solution contains `0.1molHCl`

So `CO_2` produced will be `0.1/2mol`

`or 1/2xx22.4xx0.1L=1.12L` at STP