Question

How would you determine the potential difference between two charged parallel plates that are 0.20 cm apart and have an electric field strength of 6.0 V/cm?

Answer 1

V = E d = ( 6 V/cm ) ( 0.2 cm ) = 1.2 volts

Explanation:

Electric Field is Force per unit charge E = F/q
Electric Potential is Work per unit charge V = W / q
Work is Force x distance W = F d
So V = F d / q = F/q d = E d
V = E d