Question

How many moles of iron oxide are present in a mass of `16*kg`?

Answer 1

Well the molar mass of ferric oxide, `Fe_2O_3`, is `159.69*g*mol^-1`....

Explanation:

But iron has a particularly rich oxidation chemistry. We don't know whether all the `16*kg` mass was ferric oxide, or ferrous oxide, or `Fe_3O_4` or hydrous iron oxides.....Clearly you can work out the molar quantity if all the rust is present as `Fe_2O_3`....

`"Moles of ferric oxide"=(16xx10^3*g)/(159.69*g*mol^-1)=??mol.`