Step 1) Divide each side of the equation by #color(red)(6)# to eliminate the parenthesis while keeping the equation balanced:
#-102/color(red)(6) = (6(-3x - 2))/color(red)(6)#
#-17 = (color(red)(cancel(color(black)(6)))(-3x - 2))/cancel(color(red)(6))#
#-17 = -3x - 2#
Step 2) Add #color(red)(2)# to each side of the equation to isolate the #x# term while keeping the equation balanced:
#-17 + color(red)(2) = -3x - 2 + color(red)(2)#
#-15 = -3x - 0#
#-15 = -3x#
Step 3) Divide each side of the equation by #color(red)(-3)# to solve for #x# while keeping the equation balanced:
#(-15)/color(red)(-3) = (-3x)/color(red)(-3)#
#5 = (color(red)(cancel(color(black)(-3)))x)/cancel(color(red)(-3))#
#5 = x#
#x = 5#