How do you solve #|8- x | \geq 13#?

1 Answer
Jul 26, 2017

See a solution process below:

Explanation:

The absolute value function takes any negative or positive term and transforms it to its non-negative form. Therefore, we must solve the term within the absolute value function for both its negative and positive equivalent.

#-13 >= 8 - x >= 13#

First, subtract #color(red)(8)# from each segment of the system of inequalities to isolate the #x# term while keeping the system balanced:

#-color(red)(8) - 13 >= -color(red)(8) + 8 - x >= -color(red)(8) + 13#

#-21 >= 0 - x >= 5#

#-21 >= -x >= 5#

Now, multiply each segment by #color(blue)(-1)# to solve for #x# while keeping the system balanced. However, because we are multiplying or dividing inequalities by a negative number we must reverse the inequality operators:

#color(blue)(-1) * -21 color(red)(<=) color(blue)(-1) * -x color(red)(<=) color(blue)(-1) * 5#

#21 color(red)(<=) x color(red)(<=) -5#

Or

#x <= -5#; #x >= 21#

Or, in interval notation:

#(-oo, -5]#; #[21, +oo)#