How do you solve #2x - 1< 7#?

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Answer 1 · 2017-07-26T01:09:16

See a solution process below:

Step 1) Add #color(red)(1)# to each side of the inequality to isolate the #x# term while keeping the inequality balanced:

#2x - 1 + color(red)(1) < 7 + color(red)(1)#

#2x - 0 < 8#

#2x < 8#

Step 2) Divide each side of the inequality by #color(red)(2)# to solve for #x# while keeping the inequality balanced:

#(2x)/color(red)(2) < 8/color(red)(2)#

#(color(red)(cancel(color(black)(2)))x)/cancel(color(red)(2)) < 4#

#x < 4#