Question #47bd9

1 Answer
Jul 26, 2017

Jane sent #31# messages, Boris sent #24# messages, and Shen sent #48# messages.

Explanation:

We first list the details.

Number of messages sent by Jane #=x#.

Number of messages sent by Boris #=x-7#.

Number of messages sent by Shen #=2(x-7)#.

Total number of messages sent #=103#.

Hence, we can write:

#x+ (x-7)+2(x-7)=103#

Open the brackets and simplify.

#x+x-7+2x-14=103#

#4x-21=103#

Add #21# to each side.

#4x-21+21=103+21#

#4x=124#

Divide both sides by #4#.

#(4x)/4=124/4#

#(1cancel4x)/(1cancel4)=31#

#x=31#

Jane sent #31# messages.

Boris sent #(x-7)=(31-7)=24# messages.

Shen sent #2(x-7)=2xx24=48# messages.

To check:

#31+24+48=103#