How many aluminum-based electrons are present in a salt where there is an #81*g# mass of aluminum ions....?

1 Answer
anor277
Jul 26, 2017

How many aluminum-based electrons in a salt where there is an #81*g# mass of aluminum ions....?

Explanation:

Well, we take the quotient, #(81*g)/(27*g*mol^-1)=3*mol#.

And thus there are #3 *mol# of aluminum ions, and since there are 10 electrons per #Al^(3+)# ions (for #Al, Z=13)#, there are #30*mol# of aluminum electrons.

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