What is the concentration in #"%w/v"# of sodium sulfate when #"9.74 g"# of it is placed into a #165# volume?

1 Answer
Jul 26, 2017

Well... #165# what? I assume #"mL"# (because who would ever drop #"9.74 g"# of something in a huge #"165 L"# vat?)...

And thus, with no other assumptions...

#c_(Na_2SO_4) = ("9.74 g Na"_2"SO"_4)/("165 mL soln")#

#%w//v# is defined for a solute mass in #"g"# and a solution volume in #"mL"#, so we are basically done...

#color(blue)(c_(Na_2SO_4)) = 0.0590 xx 100% = color(blue)(5.90% w//v)#