Question

Question #a8413

Answer 1

`5(7)^(2x )= 80`

`7^(2x) = 16`

`x = 1/2log_7(16)`

Now, plug in x.

`7^(3/4x)= 7^(3/8log_7(16))`

`= 7^(log_7(16^(3/8)))`

`=16^(3/8) = 2sqrt(2)`