If #c(x) = 5/(x-2)# and #d(x) = x+3#, what is the domain of #(cd)(x)#?

1 Answer
Jul 27, 2017

#x inRR,x!=2#

Explanation:

#(cd)(x)=5/(x-2)xx(x+3)=(5(x+3))/(x-2)#

#"the denominator of (cd)(x) cannot be zero as this "#
#"would make it undefined. Equating the denominator"#
#"to zero and solving gives the value that x cannot be"#

#"solve "x-2=0rArrx=2larrcolor(red)" excluded value"#

#rArr"domain is "x inRR,x!=2#