How do you solve #6d = - 78#?

1 Answer
smendyka
Jul 27, 2017

See a solution process below:

Explanation:

Divide each side of the equation by #color(red)(6)# to solve for #d# while keeping the equation balanced:

#(6d)/color(red)(6) = -78/color(red)(6)#

#(color(red)(cancel(color(black)(6)))d)/cancel(color(red)(6)) = -(6 xx 13)/color(red)(6)#

#d = -(color(red)(cancel(color(black)(6))) xx 13)/cancel(color(red)(6))#

#d = -13#

Related questions
Impact of this question
594 views around the world
You can reuse this answer
Creative Commons License