Question

How do you identify the axis of symmetry and vertex of `f(x) = -x^2-2x-1`?

Answer 1

Vertex:
`(-1, 0)`

Axis of symmetry:
`x = -1`

Explanation:

`f(x) = ax^2 + bx + c`

Vertex:
`(-b/(2a), f(-b/(2a)))`

Axis of symmetry:
`x = -b/(2a)`