How do you solve #6x + 1= - 109- 5x#?

1 Answer
Jul 28, 2017

See a solution process below:

Explanation:

Step 1) Subtract #color(red)(1)# and add #color(blue)(5x)# to each side of the equation to isolate the #x# term while keeping the equation balanced:

#6x + 1 - color(red)(1) + color(blue)(5x) = -109 - 5x - color(red)(1) + color(blue)(5x)#

#6x + color(blue)(5x) + 1 - color(red)(1) = -109 - color(red)(1) - 5x + color(blue)(5x)#

#(6 + color(blue)(5))x + 0 = -110 - 0#

#11x = -110#

Step 2) Divide each side of the equation by #color(red)(11)# to solve for #x# while keeping the equation balanced:

#(11x)/color(red)(11) = -110/color(red)(11)#

#(color(red)(cancel(color(black)(11)))x)/cancel(color(red)(11)) = -10#

#x = -10#