What is the value of #1/3x^3+5.4y# when #x=3# and #y=2#?

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Answer 1 · 2017-07-28T03:03:46

#19.8#

Substitute #3# for #x# and #2# for #y# in the given expression and evaluate.

So #1/3x^3+5.4y# becomes...

#1/3(color(blue)(3))^3+5.4(color(red)(2))#

Following our order of operations:

#=1/3(27)+10.8#

#=27/3+10.8#

#=9+10.8#

#=19.8#