How do you solve #-4x - 5= - 25- 6x#?

Question

773 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-07-28T03:33:21

See a solution process below:

Step 1) Add #color(red)(5)# and #color(blue)(6x)# to each side of the equation to isolate the #x# term while keeping the equation balanced:

#-4x - 5 + color(red)(5) + color(blue)(6x) = -25 - 6x + color(red)(5) + color(blue)(6x)#

#-4x + color(blue)(6x) - 5 + color(red)(5) = -25 + color(red)(5) - 6x + color(blue)(6x)#

#(-4 + color(blue)(6))x - 0 = -20 - 0#

#2x = -20#

Step 2) Divide each side of the equation by #color(red)(2)# to solve for #x# while keeping the equation balanced:

#(2x)/color(red)(2) = (-20)/color(red)(2)#

#(color(red)(cancel(color(black)(2)))x)/cancel(color(red)(2)) = -10#

#x = -10#