On what interval(s) is the function #f(x)=5/x+58# increasing?

1 Answer
Jul 29, 2017

#f# is not #uarr# in any interval contained in #RR-{0}.#

Explanation:

Recall that, a function (fun.)

#f" is increasing "(uarr), if f'(x) > 0.#

For given fun. #f," we have, "f'(x)=-5/x^2 < 0, AA x in RR-{0}.#

Hence, it is not #uarr# in any interval contained in #RR-{0}.#