What molar quantity is associated with a #0.44*g# mass of #"carbon dioxide"#?

1 Answer
anor277
Jul 29, 2017

We solve the quotient.......#"mass"/"molar mass"# to get the number of moles........

Explanation:

And so here.........we gets..........#(0.44*g)/(44.01*g*mol^-1)=0.010*mol# with respect to #CO_2#.

But one mole specifies by definition, #N_A, "Avogadro's number"# of molecules, where #N_A-=6.022xx10^23*mol^-1#.

And thus number of individual #CO_2# molecules is given by the product..#6.022xx10^23*mol^-1xx0.010*mol-=6.022xx10^21# individual molecules of #CO_2#. How many carbon atoms, and how many oxygen atoms does this molar quantity represent?

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