Question #e6cad

1 Answer
Bill K.
Jul 30, 2017

The answer is #(g\circ h)(3)=24#.

Explanation:

By definition, #(g\circ h)(3)=g(h(3))# (plug the output of the inner function into the outer function).

Since #h(3)=3^{2}-2=9-2=7# and #g(7)=3*7+3=21+3=24#, it follows that #(g\circ h)(3)=24#.

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