How do you solve #4a + 3( a + 1) = 24#?

1 Answer
Jim G.
Jul 31, 2017

#a=3#

Explanation:

#"distribute bracket and collect like terms on left side"#

#4a+3a+3=24#

#rArr7a+3=24#

#"subtract 3 from both sides"#

#7acancel(+3)cancel(-3)=24-3#

#rArr7a=21#

#"divide both sides by 7"#

#(cancel(7) a)/cancel(7)=21/7#

#rArra=3#

#color(blue)"As a check"#

substitute this value into the left side of the equation and if equal to the right side then it is the solution.

#(4xx3)+(3xx4)=12+12=24=" right side"#

#rArra=3" is the solution"#

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